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3U HDDs lose storage space when mixed with other capacity's?

C

Chaos Theory

Active member
My 3U server is two thirds populated with 4TB drives. My supplier can't get any more 4TB drives do I've ended up buying three 6TB drives instead.

He tells me that when mixing drives of different capacities, the the first 2TB of the first two new drives is lost to 'the system' so instead of getting 18TBs of available space, I'm only gong to get 14TBs.

Is this correct and can somebody explain why?

Many thanks :)
 
That is correct. The first drive you put in will be the largest drive in the system, so it will become the hot spare. A hot spare must be able to replace any drive that goes down and that means it must be the largest drive in the array. If your 6TB drive became a data drive, then how would the hot spare replace it in the event of a drive failure? This first 6TB drive will free up the 4TB drive for data. +4TB storage.

The parity drive is the second largest drive in the system (or the largest if a 1U server which has no hot spare). Your second 6TB drive put in would become the parity drive, freeing up the 4TB existing parity drive for data. +4 more TB storage

The third 6TB drive you put in would not be larger than the parity or hot spare drives, so it can be immediately used for data. +6 more TB storage.

+4+4+6= 14TB.

Best regards,
Mike
 
Great. Thank you very much for the explanation.

I'm assuming that any further 6TB drives added would offer the full 6TB capacity as two of the three recent additions are now the hot spare and parity drives?
 
That is correct, only the first Two drives are allocated to parity (RAID) and Hot Spare, any additional drives will give you the full 6TB's.


Jim
 
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